36 r = radius c = circumference Not expecting to finish this entry today, but have gotten into the substance of it far enough to show the confusion therein. This search had its origin in March of 1966. Shortly thereafter I abandoned it. Yesterday I began addressing it again. Circumference = 2 x pi x radius. Therefore, if the radius is 1/2 inch, the circumference = pi = 3.14159265, which is the pi value being used here.

My project in 1966 was to see if the circumference of a circle could be determined without pi. This led me to considering the 90° arc with the notion that with the aid of a protractor I could draw interlocking circles and so establish a straight line that equalled the length of a circle's circumference divided by "4", or approximately did.I may scan my original calculations (which I uncovered several days back while looking for something else) and show them here, even though upon inspecting them then I became uneasy about my conclusions in 1966. Could be my conclusions were correct and I simply no longer understand them. Moot, moot. I now have new conclusions. Let r = one inch. [ Spotty storms are meandering in. ] c = 6.28318530 /4 = 1.57079633 = pi/2 I then found that 4/7 = .57142857 Today I found that 1.57079633 divided by 11 = .14279967 and that 7 x .14279967 = .99959766 which is quite close to one inch. However, I then proceeded to r = 2 (two inches) where c = 12.56637060 and /4 = pi but pi/11 = .28559933 and 7 x that = 1.99919532 which comes to a loss of .00040234 And so I then proceeded to r = 3 where c = 18.84955590 and /4 = 4.712388898 and 4.71238898/11 = .42839900 and 7 x that = 2.99879298 which comes to loss of .00080468 from the r = 1 result, meaning that there is a loss of .00040234 per inch and consequently a loss of .00005748 per 1/7 of an inch, and of .00063225 at 11/7. 5:50 PM - The .00040234 per-inch loss bothered me; so I ventured on. 1/7 = .14285714 1/56 = .01785714 whereat I tried x 9 and got .16071429 At this juncture I returned to my trial-by-error habit because I knew what I was seeking was far off. Finally upon dividing .16071429 by 399.45 (oh, yes) I got .00040234. So, I needed to know what 56 x 399.45 equalled. Hmmph!: how does 22369.2 strike you? Indeed it was far off. 1/22369.2 = .00004470 Next question: How important is the .2? Turns out that at eight out, not seemingly significant. 1/22369 = .00004470 But still I ventured, as I wanted to know how 22369 related to 7. It doesn't. I then tried 3, and it didn't either. This made me wonder if 22369 was either a prime number or a square; so I minused 1 from it and divided by 8. Result: 2796. At that point I stopped. And now I need to look at my earlier entry regarding terms in the natural number summation sequence. Hiatus. 8:47 PM - Fact: The remainder of an odd square - 1 into which 4 is divided always equals an even integer which is the product of two adjacent integers, and the sum of those two adjacent integers always equals the square root of the odd square. Example: 17 x 17 = 289 288/4 = 72 and 8 x 9 = 72 and 8 + 9 = 17 - Given this fact, 22369 is not an odd square/ because 4 divided into 22368 equals 699, which is not an even integer. It is still possible 22369 is a prime number since 22368 is evenly divisible by both "3" and "6" but I think that does not matter. 1/22370 also equals .00004470. 22370/2 = 11185. 1/22372 also equals .00004470. 22372/7 = 3196. 22372/4 = 5593. 3196 x 4 = 12784 and 12784 + 22372 = 35156 and 35156/11 = 3196. - .00040234/.00004470 = 9.00089486. .00004470 x 9 = .00040230 which puts the result off by .00000004. But what the heck is 1/22372 of an inch? The closest unimaginable ruler number is 1/16384. Then again, rulers don't bother with sevenths of an inch either. Whatever, 12784 + 9 = 12793 or 9/22372 more than 4/7 of an inch. Now what? Back to 57079633. ... Wait! I should be moving lower. 11:44 PM - Just discovered "13" divides into 57079633 evenly, getting 4390741. I should be in bed. Tomorrow perhaps. May 27, 2008 7:26 AM - Other findings included 12771/22374 = .57079646, but after truncating 2506218.849 to 2506219 and dividing that integer by 4390741, .57079636 arrived/ because (I surmise) that while 13 divides evenly into 57079633 it does not divide evenly into 4390741. 13 divides evenly into 4390737. At nine out, .570796364 arrives. My calculator does not show ten zeros beyond the decimal point, and since I'm done with hunting, somewhere between .00000003 and .00000004 sits the error. 1/4390741 = .00000023 or .000000228. 2506219 + 4390741 = 6896960; 1.57079633/6896960 = .00000023; .00000023 x 4390741 = .99999998 of an inch. At .000000228 it becomes 1.001088948. 1.001088948 - .99999998 equals .001088968. Under, over, the yard north of my bedroom win- dow is happily banded with white clover, but the dandelions which banded it last week are now nowhere to be seen. 1:48 PM - Among other activities, went out to take some photos and did find several d-lions. At r = 2 inches c = 12.56637060 and c/4 = pi = 3.14159265 3.14159265/6896960 = .00000046 and 4390741 x .00000046 = 1.99999995 loss per inch of .00000003 (2.5) At r = 3 inches c = 18.8495590 and c/4 = 4.71238975 4.71238975/6896960 = .00000068 and 4390741 x .00000068 = 2.99999993 loss per inch of .00000002 (2.33) - This is much closer, but had to go into outer space to get it. - Recap: 4/7 = .57142857 2506219/4390741 = .57079636 target .57079633 Sounds like the robin is practicing a new tune. It has a falsetto finishing note. May 29, 2008 2:12 PM - Went out to 9 on my calculator. 3.141592654/2 = 1.570796327 and after some t-and-e chose to use .570796330 because two integers, both of which happened to be divisible by 15, equalled it. So 250621905/439074135 became 16708127/29271609. Now, if I use the smaller integers, I first need to divide 1.570796330 by 15 which equals .104719755; and then divide this by 45979736 (16708127 + 29271609). Either way, the result is .000000002. 250621905 + 439074135 = 689696040. 1.570796330 divided by 689696040. [ Much of today's entry is calculator-related junk. My attempt to go out nine has failed. Am unable to verify calculations. ] - See this Wikipedia page on Pi. May 30, 2008 4:06 PM - About yesterday's numbers: Dividing 45979736 by 15 was wrong. The numbers used relate to a circle with a radius of one inch, making 2 x pi the circumference and division by 4 approximately equal to 1.57079633. After the divisions by 15, the essential integers are 16708127, 29271609, and 45979736. (However close these are to 4/7, 7/7, and 11/7, the 1.57079633 straight line represented by 45979736/29271609 can only be imagined.) Found a way to get the answers I needed from my calculator. I eliminated the decimal point in 1.57079633 when I divided it by 45979736. That gave me 3.416279576 which truncating to 3.41627958 proved best. This is a deceptive number in that it looks a bit like pi, but it has nothing to do with pi. When this number is multiplied by 29271609, my c-toy displays 100,000,000.1 or 1.000000001 after the decimal point is returned to its proper location. All these calculations and the need to verify them entailed more effort than it probably was worth. If 3.14159265 is allowed to equal pi, 6.2831853 (2 x pi) equals the circle's c. If 1.57079633 is allowed to equal c/4, 6.28318532 = the circle's c. #Brian A. J. Salchert

is a tiny wandering imaginary dinosaur which migrated from AOL in October of 2008.

## About Me

- brian (baj) salchert
- Rhodingeedaddee is my node blog. See
*my other blogs*and*recent posts*.

## Guide

[6-16-2009 Update Insert: Most of what is in this space is now moot. I found out what I was doing wrong and have reinstated Archives and Labels searches. They do work. However, in certain cases you may prefer Labels to Archives. Example: 1976 Today begins in November of 2006 and concludes in December of 2006, but there are other related posts in other months. Note: Labels only shows 20 posts at a time. There are 21 hubs, making 21 (which is for 1976 Today) an older hub.] ********************************* to my online poems and song lyrics using Archives. Use hubs for finding archival locations but do not link through them. Originally an AOL Journal, where the archive system was nothing like the system here, this blog was migrated from there to here in October of 2008. Today (Memorial/Veteran's Day, May 25, 2009) I discovered a glitch when trying to use a Blogger archive. Now, it may be template-related, but I am unable to return to S M or to the dashboard once I am in the Archives. Therefore, I've decided on this approach: a month-by-month post guide. The sw you see in the codes here stood for Salchert's Weblog when I began it in November of 2006. It later became Sprintedon Hollow. AOL provided what were called entry numbers, but they weren't consistent, and they didn't begin at the first cardinal number. That is why the numbers after "sw" came to be part of a post's code. ************** Here then is the month-by-month post guide: *2006* November: 00001 through 00046 - December: 00047 through 00056 -- *2007* January: 00057 through 00137 - February: 00138 through 00241 - March: 00242 through 00295 - April: 00296 through 00356 - May: 00357 through 00437 - June: 00438 through 00527 - July: 00528 though 00550 - August: 00551 through 00610 - September: 00611 through 00625 - October: 00626 through 00657 - November: 00658 through 00729 - December: 00730 through 00762 -- *2008* January: 00763 through 00791 - February: 00792 through 00826 - March: 00827 through 00849 - April: 00850 through 00872 - May: 00873 through 00907 - June: 00908 through 00931 - July: 00932 through 00955 - August: 00956 through 00993 - September 00994 through 01005 - October: 01006 through 01007 - November: 01008 through 01011 - December: 01012 through 01014 -- *2009* January: 01015 through 01021 - February: 01022 through 01028 - March: 01029 through 01033 - April: 01034 through 01036 - May: 01037 through 01044 - ******************************************************* 1976 Today: 2006/11 and 2006/12 -- Rooted Sky 2007: 2007/01/00063rsc -- Postures 2007: 2007/01/sw00137pc -- Sets: 2007/02/sw00215sgc -- Venturings: 2007/03/00216vc -- The Undulant Trees: 2007/03/00266utc -- This Day's Poem: 2007/03/00267tdpc -- Autobio: 2007/04/sw00316ac -- Fond du Lac: 2007/04/00339fdl -- Justan Tamarind: 2007/05/sw00366jtc -- Prayers in December: 2007/05/sw00393pindc -- June 2007: 2007/06/sw00440junec -- Seminary: 2007/07/sw00533semc -- Scatterings: 2008/08/00958sc ** Song Lyrics: 2008/02/sw00797slc ********** 2009-06-02: Have set S M to show 200 posts per page. Unfortunately, you will need to scroll to nearly the bottom of a page to get to the next older/newer page.

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## Monday, May 26, 2008

### sw00905math--find-c-with-straight-line

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